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➡HERE IS YOUR ANSWER⬇
"Numbers fly through imagination..."
♧♧RULES♧♧
When a number is divisible by 3, the sum of its digits be divisible by 3 also.
♧♧Solution♧♧
In this problem, we will find the smallest digit only.
a)
Let, the digit is = x.
Then,
3 + x + 8 = 3k (for any integer k)
=> 11 + x = 3k
When x = 1, the sum (11+x) = 12 is surely divisible by 3.
So, the required number is = 318.
b)
Let, the digit is = y.
Then,
9 + 6 + y + 7 = 3k' (for any integer k')
=> 22 + y = 3k'
When y = 2, the sum (22+y) = 24 is surely divisible by 3.
Therefore the required number is = 9627.
⬆HOPE THIS HELPS YOU⬅
"Numbers fly through imagination..."
♧♧RULES♧♧
When a number is divisible by 3, the sum of its digits be divisible by 3 also.
♧♧Solution♧♧
In this problem, we will find the smallest digit only.
a)
Let, the digit is = x.
Then,
3 + x + 8 = 3k (for any integer k)
=> 11 + x = 3k
When x = 1, the sum (11+x) = 12 is surely divisible by 3.
So, the required number is = 318.
b)
Let, the digit is = y.
Then,
9 + 6 + y + 7 = 3k' (for any integer k')
=> 22 + y = 3k'
When y = 2, the sum (22+y) = 24 is surely divisible by 3.
Therefore the required number is = 9627.
⬆HOPE THIS HELPS YOU⬅
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