Math, asked by Anonymous, 1 year ago

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Answered by DharamveerSingh
5
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Answered by abhi569
10
first draw a diagonal,

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in square

as we know that the area of square = side^2

here,

784 = side^2

28 = side

now,

by pythagoras theorem,

side^2 + side^2 = diagonal^2 

28^2 + 28^2 = diagonal^2

784 + 784 =diagonal^2

1568  = diagonal^2

39.6 is the approximate value of diagonal of square,

Now,

diagonal of square  =  diameter of circle 

39.6 = diameter of circle 

radius = 39.6/2 = 396/20 

19.8 cm = radius of circle 

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a new triangle is formed,

now,


as the triangle is right-angled triangle,

area = height*base/2

Now,

area = (28*28)/2 =784/2 = 392cm^2
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in  circle,

area of circle = (22*r*r)/7

Now,

area of circle =  (22*19.8*19.8)/7  = 1232.125

area of semicircle = (1232.125)/2 = 616.06 = 616 (appro. value)

now,

area of shaded region = 616 - 392 = 224cm^2


then


option A is correct (area of shaded region is 224cm^2)



i hope this will help you


-by ABHAY






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