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first draw a diagonal,
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in square
as we know that the area of square = side^2
here,
784 = side^2
28 = side
now,
by pythagoras theorem,
side^2 + side^2 = diagonal^2
28^2 + 28^2 = diagonal^2
784 + 784 =diagonal^2
1568 = diagonal^2
39.6 is the approximate value of diagonal of square,
Now,
diagonal of square = diameter of circle
39.6 = diameter of circle
radius = 39.6/2 = 396/20
19.8 cm = radius of circle
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a new triangle is formed,
now,
as the triangle is right-angled triangle,
area = height*base/2
Now,
area = (28*28)/2 =784/2 = 392cm^2
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in circle,
area of circle = (22*r*r)/7
Now,
area of circle = (22*19.8*19.8)/7 = 1232.125
area of semicircle = (1232.125)/2 = 616.06 = 616 (appro. value)
now,
area of shaded region = 616 - 392 = 224cm^2
then
option A is correct (area of shaded region is 224cm^2)
i hope this will help you
-by ABHAY
______________________________________
in square
as we know that the area of square = side^2
here,
784 = side^2
28 = side
now,
by pythagoras theorem,
side^2 + side^2 = diagonal^2
28^2 + 28^2 = diagonal^2
784 + 784 =diagonal^2
1568 = diagonal^2
39.6 is the approximate value of diagonal of square,
Now,
diagonal of square = diameter of circle
39.6 = diameter of circle
radius = 39.6/2 = 396/20
19.8 cm = radius of circle
_______________________________________________
a new triangle is formed,
now,
as the triangle is right-angled triangle,
area = height*base/2
Now,
area = (28*28)/2 =784/2 = 392cm^2
_____________________________________________
in circle,
area of circle = (22*r*r)/7
Now,
area of circle = (22*19.8*19.8)/7 = 1232.125
area of semicircle = (1232.125)/2 = 616.06 = 616 (appro. value)
now,
area of shaded region = 616 - 392 = 224cm^2
then
option A is correct (area of shaded region is 224cm^2)
i hope this will help you
-by ABHAY
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