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Step-by-step explanation:
1. when a traversal cuts two parallel line thenthe two angles which are on the same side of traversal are supplementary
here
angle EBA =180-angleBED
angleEBA=180-(65+38)=180-103=77
abgle BGE=65 as isosceles triangle
now angle GBE=180-(65+65)=180-130=50
then angle GBA=77-50=27
2. angle QMR=180-(y+angle QRM)
2 angle QMR=180-y
angle QMR=90-y/2
when a traversal cuts two parallel line thenthe two angles which are on the same side of traversal are supplementary
now angle y=180-(angle QMR+x)
angle y=180-(90-y/2+x)
y=90+y/2-x
y-y/2=90-x
y=180-2x
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