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given ac= ab = ad
angle ABC =angle ACB. (angles opposite to equal sides of ∆)
angle ADC= angle ACD. (same property)
angle BAC= angle ADC + angle ACD.
(ext. angle property)
angle DAC= angle ABC + angle ACB
(same property)
angle BCD= angle ACB+ angle ACD
= angle DAC/2+ angle BAC/2
angle DAC + angle BAC= 180°
(linear pairs of angles)
DAC/2+BAC/2=(DAC+BAC)/2= 180°/2
angle BCD = 180°/2
angle BCD. = 90°
Hence proved, BCD is right angle.
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