Question

please do this two points ​

Answer 1

(i) $\sqrt{(133-89)+(25\times 4)}$

Step 1: Solve the numbers inside the square root.

$(133-89)+(25\times 4)$

$(44)+(100)$

$144$

Step 2: Find the square root of the number.

$\sqrt{144}$

First, we need to do prime factorization.

$\begin{array}{r | l} 2 & 144 \\ \cline{2-2} 2 & 72 \\ \cline{2-2} 2 & 36 \\ \cline{2-2} 2 & 18 \\\cline{2-2} 3 & 9 \\\cline{2-2} & 3 \\ \end{array}$

$144=2\times2\times2\times2\times3\times3$

Now we need to pair all the prime numbers.

$144=(2\times2)\times(2\times2)\times(3\times3)$

Now for finding the square root we will take one number from each pair and multiply.

$\sqrt{144}=2\times2\times3$

$\sqrt{144}=12$

∴ The value of $\sqrt{(133-89)+(25\times 4)}$ is $\sqrt{144}=12$.

(ii) $\frac{x}{\sqrt{1.21} } =440$

Simplifies to ⇒ $0.909091x=440$

Let's solve your equation step-by-step.

$0.909091x=440$

Step 1: Divide both sides by 0.909091.

$\frac{0.909091x}{0.909091}=\frac{400}{0.909091}$

$x=484$

∴ The value of x in the equation ⇒ $\frac{x}{\sqrt{1.21} } =440$ is $484$.