Question

please do this using heron's formula . Answer should be16,50,000 rupees . i want explanation . please don't post irrevelant answers ​

Answer 1

EXPLANATION.

• GIVEN

sides of the walls are = 122m,22m,120m.

The advertisement yield earning of = ₹5000 per m^2.

TO FIND HOW MUCH RENT DID IT PAY.

As we know that,

Area of triangle =

$\sqrt{s(s - a)(s - b)(s - c)}$

s = semi perimeter

Let a, b, c are the sides of triangle

a = 122m, 22m, 120m

Formula of semi perimeter =

$\bold {s \: = \frac{a \: + \: b \: + \: c}{2} }$

s = 122 + 22 + 120 / 2 = 132m

put the value in formula of area of triangle

√132 ( 132 - 122) (132 - 22) (132 - 120)

√132 X 10 X 110 X 12

√ 11 X 12 X 10 X 11 X 10 X 12

√ 11 X 11 X 12 X 12 X 10 X 10

11 X 12 X 10

1320m^2

Given,

earning of 1m^2 per year = 5000

earning of 1320 m^2 = 1320 X 5000

6600000

Now,

earning in 1320m^2 in 12 months

= 6600000

earning in 3 months =

6600000 X 3/12 = 1650000

Hence,

The rent pay by the company in 3 months

is = ₹ 1650000