Question

Please don't mind the handwriting
ANSWER this question correctly
IT'S URGENT.....

Answer 1

ready with your answer...
GIVEN: Angle A = 130°
TO FIND : Angle DPE = Angle CPB =?
Let angle B be 2x

So, angle C = 180 - (130 +2x) = 50–2x

So angle DCB =(50–2X)/2

Now, angle CDA = 2x + (50–2x)/2 ( as exterior angle = the sum of 2 opposite interior angles)

=> angle CDA = (2x +50)/2 = x+ 25 ……..(1)

Now,in triangle AEB, angle AEB =180 - (130+x) = 50 -x ………….(2)

So, in quadrilateral ADPE,

angle DPE = 360 -(130 + x+25 + 50-x)

=> angle DPE = 360- 205

=> angle DPE = 155°.....ans.

Answer 2

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