Math, asked by BrainlyShadow01, 9 months ago

Please don't post irrelevant answers
it's urgent.

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Answered by Anonymous
3

Answer:

= log(x²/yz) + log(y²/zx) + log(z²/xy)

= log( (x²*y²*z²)/(yz*zx*xy) )

= log( (x²y²z²)/(x²y²z²) )

= log(1)

= 0.

You can see in attachment how (x²/yz) + (y²/zx) + (z²/xy) = 0.

Follow me fast guys.

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Answered by Anonymous
1

Answer:

Answer is here

Step-by-step explanation:

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