Question

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Answer 1

(log x)^2-(log y)^2

apply the formula of a^2-b^2 ie, (a+b)(a-b)

> [(log x)-(log y)][(log x)+(log y) ]

since, (log x)-(log y)=log(x/y) and

(log x)+(log y)=log xy

Hence,

[(log x)-(log y)][(log x)+(log y) ]=logx/y*log xy

Answer 2

Answer:

(log x)²-(log y)²

apply the formula of a²-b² ie, (a+b)(a-b)

> [(log x)-(log y)][(log x)+(log y) ]

since, (log x)-(log y)=log(x/y) and

(log x)+(log y)=log xy

Hence,

[(log x)-(log y)][(log x)+(log y) ]=logx/y*log x

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