Chemistry, asked by Anonymous, 4 months ago

please don't spam........​

Attachments:

Answers

Answered by REDPLANET
8

\underline{\boxed{\bold{Question}}}

If particle has mass 2 kg and moving with speed √2 m/s at an angle 45° with x-axis then its momentum will be ?

━━━━━━━━━━━━━━━━━━━━━━━━━━━━━

\underline{\boxed{\bold{Important \;information}}}

↠ Momentum is a measurement of mass in motion.

It is a scalar quantity which is product of mass of object and velocity.

━━━━━━━━━━━━━━━━━━━━━━━━━━━━━

Mathematically,

\boxed{\boxed{\bold{p=mv}}}

Where,

p = Momentum

m = Mass of object

v = Velocity of object

━━━━━━━━━━━━━━━━━━━━━━━━━━━━━

\underline{\boxed{\bold{Answer}}}

Let's Start !

Let's make Component of velocity in both directions.

━━━━━━━━━━━━━━━━━━━━━━━━━━━━━

In x-direction,

:\implies vcos\theta = \sqrt{2} \times \frac{1}{\sqrt{2}}\; m/s

:\implies vcos\theta = 1 \;m/s

:\implies Velocity\;in\;(x-direction) = 1 \;m/s

━━━━━━━━━━━━━━━━━━━━━━━━━━━━━

In y-direction

:\implies vsin\theta = \sqrt{2} \times \frac{1}{\sqrt{2}}\; m/s

:\implies vsin\theta = 1 \;m/s

:\implies Velocity\;in\;(y-direction) = 1 \;m/s

━━━━━━━━━━━━━━━━━━━━━━━━━━━━━

Now Let's find momentum in both directions

━━━━━━━━━━━━━━━━━━━━━━━━━━━━━

In x-direction,

:\implies p_x = mv_x

:\implies p_x = 2\times 1

:\implies p_x = 2\; kg \;m/s

━━━━━━━━━━━━━━━━━━━━━━━━━━━━━

In y-direction,

:\implies p_y = mv_y

:\implies p_y= 2\times 1

:\implies p_y = 2\; kg \;m/s

━━━━━━━━━━━━━━━━━━━━━━━━━━━━━

In combined form

∴ Momentum = (2î + 2j) kg m/s

━━━━━━━━━━━━━━━━━━━━━━━━━━━━━

\boxed{\boxed{\bold{Correct \;Answer = A]\; (2i+2j) \;kg\;m/s}}}

━━━━━━━━━━━━━━━━━━━━━━━━━━━━━

Hope this helps u.../

【Brainly Advisor】

Similar questions