Question

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class 9 Maths​

Answer 1

ʜᴇʀᴇ'ꜱ yᴏᴜʀ ᴀɴꜱᴡᴇʀ

(i) $\frac{-3}{4}$ and $\frac{-2}{ 5}$

 Foremost step is to make the denominators equal by using LCM

 LCM = 20

$\frac{-3}{4}$ x 5 = $\frac{-15}{20}$

$\frac{-2}{5}$ x 4 = $\frac{-8}{20}$

THREE RATIONAL NUMBERS = $\frac{-9}{20}$, $\frac{-10}{20}$, $\frac{-11}{20}$

(ii) - 2 and 5

   We know, the denominator is 1, in case there is no denominator

THREE RATIONAL NUMBERS = - 1, 2, 3

(iii) $\frac{1}{5}$ and $\frac{1}{4}$

   Foremost step is to make the denominators equal by using LCM

   LCM = 20

$\frac{1}{5}$ x 4 = $\frac{4}{20}$

$\frac{1}{4}$ x 5 = $\frac{5}{20}$

So, here in this case we don't have sufficient Rational Numbers

So let's multiply the denominators by 10

$\frac{5}{20}$ x 10 = $\frac{50}{200}$

$\frac{4}{20}$ x 10 = $\frac{40}{200}$

THREE RATIONAL NUMBERS = $\frac{41}{200}$, $\frac{45}{200}$, $\frac{48}{200}$

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Answer 2

Answer:

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