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The steps of construction to be followed:
Step 1: For given XY+YZ+ZX = 11 cm, a line segment PQ =11 cm is drawn.
Step 2: At points, P and Q angles of angle RPQ = 30^0and \angle SQP =90^0are constructed respectively.
Step 3: Now, bisects the angle RPQ and SQP. The bisectors of these angles intersect each other at a point X.
Step 4: Construct the perpendicular bisector of PX and QX, name them as TU and WV respectively.
Step 5: Let the bisector TU intersect PQ at Y and bisector WV intersect PQ at Z. Then XY and ZY are joined.
Therefore, \triangle XYZ is the required triangle.
Step-by-step explanation:
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