Physics, asked by mamatabarrackpore, 9 months ago

please don't spam .... only answer post​

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Answered by sshravan7654
2

Answer:

In this question, let T = time taken with v1 and t= time taken with v2.

T= distance/speed

= AB/2(v1)

t= distance/speed

= AB/2(v2)

let AB= d

total time= d/2v1+d/2V2

=d/2(1/v1+1/V2)

avg speed= total distance/total time

=d/d(1/2v1+1/2V2)

=1/(1/2v1+1/2v2)

=1/2v1+2v2/4v1v2

4v1v2/(2v1+2v2)

:)

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