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Question: Solve the attached question by using the properties of quadrilaterals to find the value of x.
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Answer:
Let x=0.
45
x=0.454545454545 . . . (1)
Multiply equation (1) with 100
100x=45.4545454545 . . . (2)
Subtract equation (2) from (1)
100x−x=45.4545...−0.4545...
⇒99x= 45
⇒11x=5
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