Question

please don't spam your answer will be correct I will mark you as brainliest​

Answer 1

Answer:

$\frac{4}{9}$

Step-by-step explanation:

$(\frac{1}{216} )^{\frac{-2}{3} }$ ÷ $(\frac{1}{27} )^{\frac{-4}{3} }$

= $(\frac{1^3}{6^3} )^{\frac{-2}{3} }$  ÷ $(\frac{1^3}{3^3} )^{\frac{-4}{3} }$

= $[ (\frac{1}{6} )^3 ] ^{\frac{-2}{3} }$ ÷ $[ (\frac{1}{3} )^3 ] ^{\frac{-4}{3} }$

= $(\frac{1}{6} )^{-2}$ ÷ $(\frac{1}{3} )^{-4}$

= $6^{2}$ *  $(\frac{1}{3} )^{4}$

=   $(\frac{3*3*2*2}{3*3*3*3} )$

= $(\frac{2^2}{3^2} )$

= $\frac{4}{9}$