Question

please dont give incorrect answers i will report​

Answer 1

Given :   ∑ (2i/3)ⁿ  n = 0 to ∞

To find :  Value of summation

Solution:

∑ (2i/3)ⁿ   =  (2i/3)⁰ + (2i/3)¹ +...........................................∞

This is an infinit GP

with a = (2i/3)⁰ = 1

r = (2i/3)

Sum of infinite series =  a/(1 - r)

=  1 / (1  - (2i/3))

= 3/(3 - 2i)

= 3 (3 + 2i ) / (3 - 2i)(3 + 2i)

= (9 + 6i) / (9 - 4i²)

i² = -1

= (9 + 6i) / (9 - 4(-1))

= (9 + 6i) / (9 + 4 )

= (9 + 6i) /13

Option  1 is correct

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Answer 2

a^x=b^p, b^y=c^2p, c^z=a^4p. xyz=8p³

9+6 = 15