Chemistry, asked by patelrv01, 1 month ago

please dont spam i dont know dont write​

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Answered by MissSolitary
0

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Given,

  • Mass (m) = 10 kg
  • Acceleration (a) = 2 m/s²
  • Initial velocity (u) = 0

For no. a,

  • Time = 1 s
  • v = ?

We know that,

 \tt ⇰ \: a =  \frac{ {v}^{2} -  {u}^{2}  }{t}  \\  \\   \tt⇰ \: 2 =  \frac{ {v}^{2}  - ( {0)}^{2} }{1}  \\  \\  \tt⇰ \: 2 =  \frac{ {v}^{2}  - 0}{1}  \\  \\  \tt ⇰ \: 2 =  {v}^{2}  \\  \tt⇰ \: v =  \sqrt{2}

We also know that,

Momentum = Mass × Velocity

⇰ 10 × √2

⇰ 10√2

For no. b,

  • Time = 1.5 s
  • v = ?

 \tt ⇰ \: a =  \frac{ {v}^{2}  -  {u}^{2} }{t}  \\  \\  \tt⇰ \:2=  \frac{ {v}^{2} - ( {0)}^{2}  }{1.5}  \\  \\  \tt⇰ \: 2 \times 1.5 =  { { v }^{2}  - 0} \\  \tt⇰ \: 3 =  {v}^{2}  \\  \tt ⇰ \:  {v} =  \sqrt{3}

So,

Momentum = Mass × Velocity

⇰ 10 × √3

⇰ 10√3

For no. b,

  • Time = 2 s
  • v = ?

 \tt ⇰ \: a =  \frac{ {v}^{2}  -  {u}^{2} }{t}  \\  \\  \tt⇰ \:2=  \frac{ {v}^{2} - ( {0)}^{2}  }{3}  \\  \\  \tt⇰ \: 2 \times 3 =  { { v }^{2}  - 0} \\  \tt⇰ \: 6 =  {v}^{2}  \\  \tt ⇰ \:  {v} =  \sqrt{6}

So,

Momentum = Mass × Velocity

⇰ 10 × √6

⇰ 10√6

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