Physics, asked by randomguyforemail, 3 months ago

PLEASE DONT SPAM ITS A VERY IMPORTANT MCQ QUESTION

Centripetal acceleration is given by
a=v^2/r
a=v/r
a=vr
a=F/m

Answers

Answered by Anonymous
3

Answer:

Hope this helps you.

Explanation:

Centripetal acceleration, ac=k2rt2

where, ac=rv2

⇒rv2=k2rt2

⇒v=krt ........(1)

Tangential acceleration, at=dtdv=kr.........(2)

Tangential force acting on the particle, F=mat=mkr

Power delivered, P=F.v=Fvcosθ

∴   P=Fv=(mkr)×krt  (∵θ=0o)

⟹P=mk2r2t

Answered by bvchratnakumari1988
1

Answer:

Centripetal acceleration, a

c

=k

2

rt

2

where, a

c

=

r

v

2

r

v

2

=k

2

rt

2

⇒v=krt ........(1)

Tangential acceleration, a

t

=

dt

dv

=kr.........(2)

Tangential force acting on the particle, F=ma

t

=mkr

Power delivered, P=

F

.

v

=Fvcosθ

∴ P=Fv=(mkr)×krt (∵θ=0

o

)

⟹P=mk

2

r

2

t

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