Question

Please draw figure of above. Example Diagonals of a rectangle ABCD intersect at point O. If AC = 8 cm then find BO and if < CAD = 35° then find < ACB.

Answer 1

Answer:

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Step-by-step explanation:

here AC=8cm

<CAD=35°

and angle of the corners are 90°

Since <DAB=90°

<CAD + <CAB =90°

35°+ <CAB =90°

<CAB =90° - 35°

<CAB= 55°

So, here we know that <ABC= 90°

and In ∆ABC

<CAB + <ABC + <ACB =180°

55° + 90° + <ACB = 180°

<ACB = 180° - 145°

<ACB = 35°

hope this help you.

thanks