please draw the diagram
IF D, E, F are the mid-points of sides BC, CA and AB respectively of triangle ABC, then the ratio of the areas of triangles DEF and ABC is.
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A ΔABC and ΔDEF which is formed by joining the mid-point D,E and F of the sides AB,BC and CA of ΔABC
Refer image,
To prove: ΔDEF≅ΔEDB≅ΔCFE≅ΔFAD
Proof: DF joins mid-points of sides AB and AC respectively of ΔABC
∴DF∣∣BC [Mid-point theorem]
⇒DF∣∣BE
SImilarly, EF∣∣BD
So, quadrilateral BEFD is a parallelogram.
⇒ΔDEF≅Δ EDB (1)
(∵ DIagonal of parallelogram divides it into two congruent triangles)
Similarly, ΔDEF≅Δ CFE (2)
and ΔDEF≅Δ FAD (3)
From equation (1),(2) and (3), we get
ΔDEF≅ΔEDB≅ΔCFE≅ΔFAD
Hence, proved.
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