Please elaborate the answer, Question:- Solve (3k)²+(-k)²
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(3k)^2 + (-k) ^2
9k^2 - k^2
8k^2
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Answer:
(3k)²+(-k)²
[(3k×3k)=(3k)²]for you
therefore
9k²+k²=0 (-k × -k = +k²)
10k²=0
k²=o/10
k²=infinite (anything dividend by 0=infinite)
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