Math, asked by hahhassss33, 1 year ago

please evaluate this Integral​

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Answers

Answered by RaviMKumar
0

Answer:

log | x+1 + √(x²+2x+3) | +C

Step-by-step explanation:

∫[ dx / √(x²+2x+3)]

= ∫[ dx / √(x²+2x+1+2)]

= ∫[ dx / √((x+1)²+2)]

= ∫[ dx / √((x+1)²+(√2)²)]

= log  | (x+1) + √((x+1)²+(√2)² | + C

= log | x+1 + √(x²+2x+3) | +C

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