Question

please expand (1/x + y/3) (whole cube)

Answer 1

Answer:

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Answer 2

Answer:

using identity,

(a+b)^3= a^3 + b^3+ 3a^2b + 3ab^2

=(1/x + y/3)= 1/x^3 + y/3^3 + 3*1/x^2*y/3 + 3*1/x*y/v 3^2

=1/y3 + y3/27 +