Math, asked by shardasupriya95, 18 days ago

please expand it in full process​

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Answered by syednura715
0

Answer:

(2x+y-3z)^2

using identity

=(a+b+c)^2=a^2+b^2+c^2+2ab+2bc+2ca

=(2x)^2+(y)^2+(3z)^2+2(2x)(y)+2(y)(3x)+2(3z)(2x)

=4x^2+y^2+9z^2+4xy+6yz+12xz

Answered by ayanow209
0

Answer:

4x^2 + 16 +9z^2

Step-by-step explanation:

(2x + 4 -3z)^2

(2x×2x + 4×4 -3z×-3z)

= 4x^2 + 16 + 9z^2

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