Question

please expand this


(3a-2b+c)²​

Answer 1

Step-by-step explanation:

(3a−2b+c)²

=(3a+−2b+c)(3a+−2b+c)

=(3a)(3a)+(3a)(−2b)+(3a)(c)+(−2b)(3a)+(−2b)(−2b)+(−2b)(c)+(c)(3a)+(c)(−2b)+(c)(c)

=9a²−6ab+3ac−6ab+4b²−2bc+3ac−2bc+c²

=9a²−12ab+6ac+4b²−4bc+c²

Answer 2

Step-by-step explanation:

(3a +2b + c)²

(3a + 2b + c) (3a +2b +c )

3a(3a +2b+c)+2b(3a+2b+c)+c(3a+2b+c)

9a²+6ab+3ac+6ab+4b²+2bc+3ac+2bc+c²

9a²+12ab+6ac+4b²+2bc+2bc+c²

9a²+12ab+6ac+4b²+4bc+c²

ans.= 9a²+12ab+6ac+4b²+4bc+c²