Question

please explain any one of these two

Answer 1

30.
a^x=b
b^y=c
c^z=a
Therefore,
a=b^1/x .....1
b=c^1/y ....2
c=a^1/z ....3
put equation no. 2 in equation no 1
=>a=c^1/xy ......4
now,
put equation no. 3 in equation no 4

=>a=a^1/xyz
=>1=1/xyz
=>xyz=1


29.(writing direct answer)
a^21/b^14×b^9/a^12
=>a^21-12/b^14-9
=>a^9/b^5=a^m/b^n
by comparison we get
m=9, n=5
2n-m=2×5-9=10-9=1

Hence proved!!

Hope this helped ☺️