Question

please explain fast i need it rn​

Answer 1

Solution :-

Here,

• A car covers 2/5th of the total distance with v1 speed.

• A car covers 3/5th of the total distance with v2 speed .

Therefore,

Distance covered by car = 2s/5+ 3s/5

Now,

As we know that,

Average speed ( v) = Distance(s)/time(T)

Therefore,

Average speed of car

= s1 + s2 / s1/v1 + s2/v2

[ Time = Distance /speed ]

Put the required values,

Average speed of a car

= 2/5s + 3/5s / 2s/5v1 + 3s/5v2

= 2 /2/v1 + 3/5/v2

By taking LCM

= 5 / 2v2 + 3v1/v1v2

= 5v1v2/ 2v2 + 3v1

= 5v1v2 / 3v1 + 2v2

The average speed of car is 5v1v2/3v1+2v2 .

Hence, Option 4 is correct $.$

Answer 2

Answer:

Average speed

=> 5V1V2/3V1+2V2 .