Question

please explain friends
I will give you 5 like for this​

Answer 1

Answer:

$(3p - \dfrac{1}{6})^3$

Step-by-step explanation:

If we observe the given polynomial,

$27p^3 - \frac{1}{126} - \frac{9p^2}{2} + \frac{1}{4} p$

=> Here, 27p³ =  (3p)³ and 1/216 = (1/6)³

So, this is in the form of a³ - b³ - 3a²b + 3ab² which is equal to (a-b)³, where a =3p and b = 1/6

Hence,  

$\boxed {27p^3 - \frac{1}{126} - \frac{9p^2}{2} + \frac{1}{4} p = (3p - \dfrac{1}{6})^3}$

Let us verify once, whether the answer and question will match or not,

$(3p - \dfrac{1}{6})^3 = (3p)^3 - (\frac{1}{6} )^3 -3 (3p)^2(\frac{1}{6} ) + 3 (3p)(\frac{1}{6} )^2\\\\=> \underline{\underline { 27p^3 - \frac{1}{216} - \frac{9p^2}{4} + \frac{p}{4}}}$

Hence Verified!!

Hope it helps!

Answer 2

Step-by-step explanation:

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