Question

please explain full solution ​

Answer 1

→ An angle is ¼ of its complement what is its magnitude ?

- suppose the angle will be X

so the complement of angle will be (90-x)

now apply the situation of ¼,

$x = \frac{1}{4}(90 - x) \: \\ \\ 4x = 1(90 - x) \\ \\ 4x = 90 - x\\ \\4x - 90 + x = 0 \\ \\ 5x = 90 \\ \\ x = \frac{90}{5} \\ \\ x = 18$

the angle will be X = 18 °.

Answer 2

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→ An angle is ¼ of its complement what is its magnitude ?

- suppose the angle will be X

so the complement of angle will be (90-x)

now apply the situation of ¼,

$\begin{gathered}x = \frac{1}{4}(90 - x) \: \\ \\ 4x = 1(90 - x) \\ \\ 4x = 90 - x\\ \\4x - 90 + x = 0 \\ \\ 5x = 90 \\ \\ x = \frac{90}{5} \\ \\ x = 18\end{gathered}x=41(90−x)4x=1(90−x)4x=90−x4x−90+x=05x=90x=590x=18</p><p>$

the angle will be X = 18 °.