please explain
how answer is (c)
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r = coswt.x^ + sinwty^
differentiate wrt t
dr/dt = -wsinwt.x^ + wcoswt.y^
we know,
velocity is the change in position per unit time
e.g v = dr/dt
so, v = w( -coswt.x^ + sinwt.y^)
now take dot products of r and v
r.v ={ -wsinwt.coswt + wsinwt.coswt } =0
this is possible only when ,
v is perpendicular upon r
so, option ( c) is correct
differentiate wrt t
dr/dt = -wsinwt.x^ + wcoswt.y^
we know,
velocity is the change in position per unit time
e.g v = dr/dt
so, v = w( -coswt.x^ + sinwt.y^)
now take dot products of r and v
r.v ={ -wsinwt.coswt + wsinwt.coswt } =0
this is possible only when ,
v is perpendicular upon r
so, option ( c) is correct
Ananyasaxena:
but how a is towards origin
w is constant means tangential acceleration is zero..... so here in this case centripetal acceleration will work
centripetal acceleration is always directed towards centre
am I right @bhi??
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