please explain how solve this question.
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x = 3/5
Step-by-step explanation:
Given :-
2^7x / 2^2x = 5th root of 2^15
To find :-
Find the value of x ?
Solution :-
Given that:
2^7x / 2^2x = 5th root of 2^15
We know that
a^m / a^n = a^(m-n)
Where a = 2 , m = 7x and n = 2x
On applying this formula then
=> (2)^(7x-2x) = 5th root of 2^15
=> 2^5x = 5th root of 2^15
We know that
nth root a = a^1/n
=> 2^5x = (2^15)^1/5
We know that
(a^m)^n = a^mn
=> 2^5x = 2^(15/5)
=> 2^5x = 2^3
If bases are equal then exponents must be equal
=> 5x = 3
=> x = 3/5
Therefore, x= 3/5
Answer:-
The value of x for the given problem is 3/5
Check:-
If x = 3/5 then
LHS = 2^7x / 2^2x
=> 2^7(3/5) / 2^2(3/5)
=> 2^(21/5) / 2^(6/5)
=> 2^[(21/5)-(6/5)]
=> 2^(21-6)/5
=> 2^(15/5)
=> 2^3
=> 2×2×2
=> 8
RHS = 5th root of 2^15
=> (2^15)^1/5
=> 2^(15/5)
=> 2^3
=> 2×2×2
=> 8
LHS = RHS is true for x = 3/5
Used formulae:-
- a^m / a^n = a^(m-n)
- nth root a = a^1/n
- (a^m)^n = a^mn
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