Question

Please explain how to get the (2) in the answer to this question
Find the dimensions of a rectangle if its perimeter is 100cm and it's length is 20cm more than its breadth

Answer 1

let the breadth be x
Therefore, length-x+20 cm
ATQ,
2(x+x+20)=100
2x+20=100/2
2x=50-20
x=30/2
x=15
Therefore,
Breadth-x-15 cm
Length-x+20=15+20=35 cm

Answer 2

Answer:

Step-by-step explanation:

Let the breadth be *x*

=> Length = *x+20*

Perimeter of rectangle = 2 ( l + b )

=> 2 ( x + x + 20 ) = 100

=> 2 ( 2x + 20 ) = 100

=> 4x + 40 = 100

=> 4x = 60

=> x = 15

Therefore , length is 15 + 20 = 35

And , breadth is = 15