Question

please explain it in detail .​

Answer 1

Answer:

15 days.

Step-by-step explanation:

Solution:

A can complete work in = 30 days

Efficiency of A (A’s 1 day’s work) = 1/30

Efficiency of B (B’s 1 day’s work) = 1/30 × (125/100) = 1/24

Efficiency of C (C’s 1 day’s work) = 1/24 × (120/100) = 1/20

Let the remaining work be complete by B in x days.

According to the question

3 (1/30 + 1/24 + 1/20) + x/24 = 1

⇒ 3 [(4 + 5 + 6)/120] + x/24 = 1

⇒ 15/40 + x/24 = 1

⇒ x/24 = 1 – 3/8 ×

⇒ x/24 = (8 – 3)/8

⇒ x/24 = 5/8

⇒ x = 5/8 × 24 = 15

Short Trick:

Let Efficiency of A = 4

Efficiency of B = 4 × 5/4 = 5

Efficiency of C = 5 × 6/5 = 6

Total work = 30 × 4 = 120

Work done by A, B and C in 3 days = (4 + 5 + 6) × 3 = 45

Remaining work = 120 – 45 = 75

∴ B completes the remaining work in = 75/5 = 15 days.HOPE IT HELPS.PLEASE VOTE AND GIVE THANKS IF U LIKE IT.