Math, asked by Anushka922, 1 year ago

please explain it in detail

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Answered by dpsdurgstudent
4
[tex] \frac{2x - (2x - 3)}{3x - (4x + 3)} = - 1 \\ \frac{2x - 2x + 3}{3x - 4x - 3} = - 1 \\ \frac{3}{ - x - 3} = - 1 \\ 3 = x + 3 \\ x = 0

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Answered by independentadv
0

[(2x) ×(-2x)]-[ (2x) ×-3]

[(3x)*(-4x)] + [(3x) * +3]

= -4x+6x

-12x +9x

=2x/-2x =-1

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