Physics, asked by suhasnethi07, 11 months ago

please explain it step by step to get the brainliest answer!!!​

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Answered by ShivamKashyap08
7

\huge{\bold{\underline{\underline{....Answer....}}}}

\huge{\bold{\underline{Given:-}}}

r = 6m.

{ \theta = 90 \degree}

\huge{\bold{\underline{Explanation:-}}}

As we need to find the distance covered by the body we can use the formula of perimeter of an arc.

Which is ,

\large{\bold{ S = \frac{ \theta}{360} \times 2 \pi r}}

Here "S" is the distance covered by the particle.

Substituting the values.

\large{ \implies S = \frac{90}{360} \times 2 \pi \times 6}

\large{ \implies S = \frac{1}{4} \times 2 \pi \times 6}

\large{ \implies S = \frac{1}{ \cancel{4}} \times  \cancel{2} \pi \times 6}

\large{ \implies S = \frac{1}{ \cancel{2}} \times \pi \times \cancel{6}}

\large{\bold{ \implies S = 3 \pi \: meter}}

\huge{\boxed{\boxed{S = 3 \pi \: meter}}}

So, the distance covered is 3π meter (option---(A)).

Answered by Anonymous
4

\huge{\underline{\underline{\mathfrak{Answer \colon}}}}

From the Question,

  • Radius of the Circle,r = 6m

  • Angle subtended at the centre of the circle,∅ = 90°

To find:

The distance covered by the object

Here,

The distance covered by the object is equal to the length of the arc which makes 90° with the centre of the circle

Let "l" be the distance covered by the object

We Know that,

Arc Length is given by:

   \boxed{\boxed{\sf{l =  \frac{ \theta}{360}.2\pi \: r }}} \\

Putting the values,we get:

 \sf{l =  \frac{90}{360}  \times 2\pi \times 6} \\  \\  \implies \:  \sf{l =  \frac{12 \pi}{4} } \\  \\  \implies \:  \huge{ \sf{l = 3\pi \ m}}

  • Option(A) is correct
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