Question

please explain it to me quickly
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Answer 1

Answer:

x=40°

CED+AEF=180°

=>100°+AEF=180°

=>AEF=180-100=80°

∆AEF=180°

=>AEF+FAE+AFE=180°

=>80°+50°+AFE=180°

=>AFE=180°-130°=50°

AFE=DFB=50°

FBD+FBC=180°

=>FBD+90°=180°

=>FBD=180°-90°=90°

∆DFB=180°

=>FDB+DFB+FBD=180°

=>X+50°+90°=180°

=>X=180°-140°=40°

Hope it helped!

Answer 2

Answer:

in

angle ABC and Angle DEC

Step-by-step explanation:

In ABC

A= 50, B= 90 C=?

A-B-C

50+90+C= 180

C=180-140

C=40

Therefore,

D+E+C= 180

D+100+40=180

D=180-140

D=40