Question

please explain me how to solve it​

Answer 1

Answer:

answer is option mate

Step-by-step explanation:

if roots are not real, then

b^2-4ac<0

b<√4ac

5p<8

p<8/5

so,-8/5<p8/5

Answer 2

Answer:

Step-by-step explanation:

having no real roots ,

     $b^{2} -4ac$ < 0

    $(5p)^{2} -$( 4 × 1 × 16) < 0

   $25p^{2}$ $-64$ < 0

  $p^{2}$ >  $\frac{64}{25}$

  p >  ± $\frac{8}{5}$

$-\frac{8}{5} < p < \frac{8}{5}$

c) option is correct