Question

Please explain me only 4th option . Please I will mark u as brainliest . Please don't spam .​

Answer 1

Answer:

(d) at t = 2s particle is at the origin. Explanation: The velocity at any instant is given by v=dx/dt=u+2a(t-2) initial velocity is the velocity at t=0, putting this value we get v=u-4a which is not zero.

Answer 2

Answer:

We can write the equation as,

X=u(t−2)+

2

1

(2a)(t−2)

2

clearly, X=0 at t=2

Also, acceleration=2a when we compare the given equation with

X=ut+

2

1

at

2