Please explain me the answer! Question is shown in attacent..
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according to attachment option (4) is correct
➡because according to Archimedes principle,loss in weight of body when emersed underwater is equal to up-thrust of water. so,
w1-w2=vρg.............(1)
where v is volume,ρ is density and g is acceleration due to gravity.
➡body float with some emersed part under water. let V be volume of body and v be volume outside water.
- volume of body underwater=V-v
- weight of liquid displace=(V-v)ρg
- weight of body=Vσg
for float,
weight of liquid displace by submerged part=weight of body
(V-v)ρg=Vσg........... (2)
from equation (1) and (2) if density of ball and liquid is not same then total reading of weighting is sum of weight of ball and liquid and container
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