Please explain me the example 1.4 of the chapter 1 of the ncert physics part 1. I am not abple to get it.
Answers
Explanation:
a) i) = The electric force between an electron and a proton at a distance r apart is:
Fe = K Q1 Q2 / r^2
Fe = 9×10^9 × 1.6×10^-19 × 1.6×10^-19 / r^2
Fe = 9 × 1.6 × 1.6 × 10^-29 / r^2
= 23.04 × 10^-29 / r^2
Fg = G M1 M2 / r^2
= 6.67×10^-11 × 9.11×10^-31 × 1.67×10^-27 / r^2
= 6.67 × 9.11 × 1.67 × 10^-69 / r^2
= 101.475 × 10^-69 / r^2
Fe/Fg = 23.04 × 10^-29 / r^2 / 101.475 × 10^-69 / r^2
=23.04 × 10^-29 × 10^69 / 101.475
= 23.04 × 10^40 / 101.475
= 0.227 × 10^40
= 2.27 × 10^39
Fe/Fg = 2.3 × 10^39
ii) = Fe = 23.04 × 10^-29 / r^2
Fg = 6.67×10^-11 × 1.67×10^-27 × 1.67×10^-27 / r^2
= 6.67 × 1.67 × 1.67 × 10^-65 / r^2
= 18.602 × 10^-65 / r^2
Fe/Fg = 23.04 × 10^-29 / r^2 / 18.602 × 10^-65 / r^2
= 23.04 × 10^-29 / 18.602 × 10^-65
= 23.04 × 10^-29 × 10^65 / 18.602
= 23.04 × 10^36 / 18.602
= 1.23858 × 10^36
Fe/Fg= 1.3 × 10^36
b) = Fe = 9×10^9 × 1.6×10^-19 × 1.6×10^-19 / (10^-10)^2
=9 × 1.6 × 1.6 × 10^-29 / 10^-20
= 23.04 × 10^-29 × 10^20
Fe = 23.04 × 10^-9 N
For electron,
a = F/m = 23.04 × 10^-9 / 9.11 × 10^-31
= 23.04 × 10^-9 × 10^31 / 9.11
= 23.04 × 10^22 / 9.11
= 2.532 × 10^22
= 2.5 × 10^22 m/s^2
For proton,
a=F/m = 23.04 × 10^-9 / 1.67 × 10^-27
= 23.04 × 10^-9 × 10^27 / 1.67
= 23.04 × 10^18 / 1.67
= 13.796 × 10^18
= 1.3796 × 10^19
= 1.4 × 10^19 m/s^2
If you have any problem regarding the no.s I have puted there, then just see the question and you will find it.
Hope it will works...
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Answer:
the value of acceleration of the proton
Explanation:
2.3×10⁸ n
