Question

please explain me this ​

Answer 1

$\mathfrak{\large{\underline{\underline{Solution:-}}}}$

$\displaystyle \frac{3(y - 5)}{4} - 4y = 3 - \frac{(y - 3)}{2}$

$\displaystyle \frac{3(y - 5)}{4} - 4y + \frac{(y - 3)}{2} = 3$

$\displaystyle \frac{3(y - 5)}{4} - \frac{4y}{1} + \frac{(y - 3)}{2} = 3$

Least Common Multiple of 2 and 4 is 4

$\displaystyle \frac{3(y - 5)}{4} - \frac{4y(4)}{1(4)} + \frac{(y - 3)(2)}{2(2)} = 3$

$\displaystyle \frac{3y - 15}{4} - \frac{16y}{4} + \frac{(2y - 6)}{4} = 3$

$\displaystyle \frac{3y - 15 - 16y + 2y - 6}{4}= 3$

$\displaystyle 3y - 15 - 16y + 2y - 6= 3 \times 4$

$\displaystyle 3y - 15 - 16y + 2y - 6= 12$

$\displaystyle 5y - 21 - 16y = 12$

$\displaystyle -21 - 11y = 12$

$\displaystyle - 11y = 12 + 21$

$\displaystyle - 11y = 33$

$\displaystyle - 11y = 33$

$\displaystyle 11y = 33$

$\displaystyle y = \frac{33}{-11}$

$y = - 3$

$\Huge{\boxed{ \sf y = -3}}$

$\mathfrak{\large{\underline{\underline{Verification:-}}}}$

$\displaystyle \frac{3(-3 - 5)}{4} - 4(-3) = 3 - \frac{(-3 - 3)}{2}$

$\displaystyle \frac{3(-8)}{4} + 12 = 3 - \frac{(-6)}{2}$

$\displaystyle \frac{-24}{4} + 12 = 3 - (-3)$

$- 6 + 12 = 3 - (-3)$

$- 6 + 12 = 3 + 3$

$6 = 6$

Answer 2

Answer:-

Refer the attachment