Math, asked by Anonymous, 9 months ago

please explain me this problem​

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Answered by amansharma264
1

Answer:

1 =  {x}^{2} - 7x - 30 \\  {x}^{2} - 10x + 3x - 30 = 0 \\ x(x - 10) + 3(x - 10) = 0 \\ (x + 3)(x - 10) =0 \\  \\ 2 =  {m}^{2} + 12m - 45 \\  {m}^{2}  +15m - 3m - 45 = 0 \\ m(m + 15) - 3(m + 15) = 0 \\ (m - 3)(m + 15) = 0 \\  \\ 3 =  {m}^{2} - 42m -88 \\  {m }^{2} - 44m + 2m - 88 = 0 \\ m(m - 44) + 2(m - 44) = 0 \\ (m + 2)(m - 44) = 0 \\  \\ 4 = 81 {x}^{2} - 121 \\ it \: is \: the \: form \: of \:  {x}^{2} -  {y}^{2} \\ formula \: of \:  {x}^{2} -  {y}^{2} = (x + y)(x - y) \\(9x {)}^{2} - (11 {)}^{2} \\ (9x - 11)(9x + 11) \\  \\ 5 = 100 {x}^{2} - 35 \\5(20 {x}^{2} - 7) = 0 \\ 5 = 0 = 0 \\ (20 {x}^{2} - 7) = 0 \\  {x}^{2} =  \frac{7}{20} \\ x =  \sqrt{ \frac{7}{20} }

I hope this is your answer

Answered by MrUNKNOWN001
1

Answer:

kya mai ek chiz puch sakta hou ki aap mujhe

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