Please explain once.
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Proof ∠APQ = ∠ABC = 60° ..
.[Given] ∴ ∠APQ ≅ ∠ABC ∴ side PQ || side BC ...(i) [Corresponding angles test]
In ∆ABC,
sidePQ || sideBC ...[From (i)]
∴ AP/PB = AQ/QC ....[Basic proportionality theorem]
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