Math, asked by tekademrpego8x, 1 year ago

please explain question no. 3 i will mark you as the brainliest

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Answered by Anonymous
4

 {( {x}^{2} - 6x) }^{2}  - 8( {x}^{2}  - 6x + 8) - 64 \\ let \:  {x }^{2}  - 6x = a \\  \: then \\  {a}^{2}  - 8(a + 8) - 64 \\  {a}^{2}  - 8a - 64 - 64 \\  {a}^{2}  - 8a - 128 \\    {a}^{2}  - 16a + 8a - 128 \\ ( a - 16)(a + 8) \\ putting \: value \: of \: a \\ ( {x}^{2}  - 6x - 16)( {x}^{2}  - 6x + 8) \\ solving \: further \\ ( x - 8)(x + 2)(x - 4)(x - 2)
Answered by Dhanush03
4
(x^2-x)^2-6(x^2-x)-2(x^2-x)+12
x^2-x (x^2-x-6)-2(x^2-x-6)
(x^2-x-6)(x^2-x-2)
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