Question

Please explain reason

Answer 1

for real roots

b^2 >= 4a( 2)

b^2>= 8 a

a>= 2, b<=6

For b= 6, a= 2,3,4. ( 3 pairs)

b= 5 , a= 2,3. ( 2 pairs)

b= 4 , a= 2 ( 1 pair)

rest values are not possible as

(4)^2 = 8(2)

SO TOTAL NO OF EQUATIONS

3+2+1 = 6

Answer 2

Please see the attachment