Please explain step by step
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Step-by-step explanation:
⇒ AD is a median of △ABC.
⇒ Draw AE⊥BC.
In right angled △AEB,
⇒ (AB)2=(AE)2+(BE)2 [ By Pythagoeas theorem ] --- ( 1 )
In right angled △ACE,
⇒ (AC)2=(AE)2+(EC)2 [ By Pythagoeas theorem ] ---- ( 2 )
Adding ( 1 ) and ( 2 ),
⇒ (AB)2+(AC)2=(AE)2+(BE)2+(AE)2+(EC)2
⇒ (AB)2+(AC)2=2(AE)2+(BD−ED)2+(ED+DC)2
⇒ (AB)2+(AC)2=2(AE)2+(BD)2−2BD.ED+(ED)2+(ED)2+2ED.DC+(DC)2
⇒ (AB)2+(AC)2=
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