please explain the above formula in detail.
Answers
Hi my dear friend here is ur answer
When a bar magnet is bend into the shape of a horseshoe, the magnetic field between the poles is nearly uniform and usually quite strong. B = μ0I/(2πr). This equation is derived from one of Maxwell's equations called Ampere's law. Your fingers curl into the direction of the magnetic field produced by the current.
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Question:
To derive the formula of magnetic field due to a long straight current carrying conductor.
Answer:
Explanation:
↬ To derive this formula first we have to know Ampere's circuital law.
↬ Ampere's law state that the line integral of the magnetic field () around any closed circuit is equal to μ₀ times the total current (I) passing through the closed circuit.
where μ₀ is the magnetic constant.
↬ Ampere's circuital law is valid for any assembly of current.
Magnetic field due to a long straight current carrying wire:
↬ Consider a current carrying conductor XY.
↬ Consider a point P which is at a distance of r from the centre of the wire.
↬ Here we have to find the magnetic field at point P.
↬ Consider a small current element at P. Here the direction of and dl are in the same direction. Hence the angle between them is zero.
↬ Hence the line integral of the closed loop is given by,
↬ Here θ = 0
↬ Hence,
↬ Here is the total length or the perimeter of the circular path.
↬ That is,
↬ Therefore
↬ Now by Ampere's circuital law we know that,
↬ Hence,
↬ Taking 2π r to the RHS side we get,
where I = current through the conductor
r = perpendicular distance from the wire
↬ The direction of magnetic field is given by the right hand thumb rule.