Please explain the Action of Acetylcholine in Chemical Synapse of Brain
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Pre-syneptic neurons ,contains syneptic vesicles, which is filled with Acteylcholine.
•Action of Acetylcholine in Chemical Synapse :-
Synapse gap is broad and about 20nanometer in diameter. When impulse reach to terminal end of nerve fibre, channel of Ca of presyneptic membrane will be open, now Ca enter into pre-synaptic neurons , through channel.
These Ca attract the synaptic vesicle, due to this reason synaptic vesicle ,move towards pre-synaptic membrane and secrete acetylcholine , by exocytosis. Acetylcholine with the receptor molecules of post synaptic membrane .
It results into development of depolarisation condition called post membrane by opening of Na channel.
Acetylcholine ------------> Acetic acid + choline.
(in the presence of esterase)
After depolarisation in the presence of esterase enzymes acetylcholine break down into Acetic acid and choline radical.
Both acetic acid and choline radical return to post synaptic neuron and bind together to form acetylcholine , it is used again.
The new potential development may be either excitatory ( i.e - acetylcholine) or inhibitory (GABA) -gamma - amino buteric acid .GABA open the channel of the chloride of axolema chloride move fastly from ECS to ICA through channel it results into development of hyperpolarization condition of nerve fibre .
I.e (-ve charge is more in ICF and it inhibits transmission of impulse .
•Action of Acetylcholine in Chemical Synapse :-
Synapse gap is broad and about 20nanometer in diameter. When impulse reach to terminal end of nerve fibre, channel of Ca of presyneptic membrane will be open, now Ca enter into pre-synaptic neurons , through channel.
These Ca attract the synaptic vesicle, due to this reason synaptic vesicle ,move towards pre-synaptic membrane and secrete acetylcholine , by exocytosis. Acetylcholine with the receptor molecules of post synaptic membrane .
It results into development of depolarisation condition called post membrane by opening of Na channel.
Acetylcholine ------------> Acetic acid + choline.
(in the presence of esterase)
After depolarisation in the presence of esterase enzymes acetylcholine break down into Acetic acid and choline radical.
Both acetic acid and choline radical return to post synaptic neuron and bind together to form acetylcholine , it is used again.
The new potential development may be either excitatory ( i.e - acetylcholine) or inhibitory (GABA) -gamma - amino buteric acid .GABA open the channel of the chloride of axolema chloride move fastly from ECS to ICA through channel it results into development of hyperpolarization condition of nerve fibre .
I.e (-ve charge is more in ICF and it inhibits transmission of impulse .
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