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Just factorise the given equation.
x² - 6x + 5 = 0
x² - x - 5x + 5 = 0
x(x - 1) - 5(x - 1) = 0
(x - 1)(x - 5) = 0
Thus,
x = 1 or x = 5
Given that p and q are roots of the quadratic equation. Thus let,
p = 1 and q = 5.
Then,
p³ + q³ = 5³ + 1³ = 125 + 1 = 126
On taking p = 5 and q = 1, we still get 126.
Thus the answer is (d) 126.
#answerwithquality
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