Please explain the answer of this question to me....
Answers
this is based on wheatstone bridge,
by that digram we have , R1= 2 , R2 = 2 , R3 = 2 , R4 = 2 and other R5 = 10 ohm.
so R1 / R2 = 2/2 = 1.
and similarly R3 / R4 =1 .
so we will neglect the 10 ohm reistance by that wheatsone principle ..
now , R1 and R2 conmected in series and R3 and R4 connected in swries.
so we will get Rseries= 4 and other Rs (equ series resistance)=4 .
and now their total equ. resitance are in pareel so ..
total resitance = 1/4 + 1/4
= 2 ohm.
hope it will help u mark as brainlist ans.
Answer:
by that digram we have , R1= 2 , R2 = 2 , R3 = 2 , R4 = 2 and other R5 = 10 ohm.
so R1 / R2 = 2/2 = 1.
and similarly R3 / R4 =1 .
so we will neglect the 10 ohm reistance by that wheatsone principle ..
now , R1 and R2 conmected in series and R3 and R4 connected in swries.
so we will get Rseries= 4 and other Rs (equ series resistance)=4 .
and now their total equ. resitance are in pareel so ..
total resitance = 1/4 + 1/4
= 2 ohm.